Thank you for reporting, we will resolve it shortly
Q.
In the circuit figure, the voltmeter reads $30V$ . The resistance of the voltmeter is
NTA AbhyasNTA Abhyas 2022
Solution:
The potential difference across $300 \, \Omega=60-30=30V$
Therefore the effective resistance of voltmeter resistance $R$ and $400 \, \Omega$ in parallel will be equal to $300 \, \Omega$ , as 60 V is equally divided between two parts.
So, 300 $=\frac{R \times 400}{R + 400}$
or $300R \, +120000=400R \, or \, R=1200 \, \Omega$