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Physics
In the circuit diagram shown below, the magnitude and direction of the flow of current, respectively, would be <img class=img-fluid question-image alt=Question src=https://cdn.tardigrade.in/q/nta/p-8ol9h6lh0fgqqfxa.jpg />
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Q. In the circuit diagram shown below, the magnitude and direction of the flow of current, respectively, would be
NTA Abhyas
NTA Abhyas 2022
A
$\frac{7}{3}A$ from $a$ to $b$ via $e$
B
$\frac{7}{3}A$ from $b$ to $a$ via $e$
C
$1A$ from $b$ to $a$ via $e$
D
$1A$ from $a$ to $b$ via $e$
Solution:
$I=\frac{10 - 4}{1 + 2 + 3}=1 \, A$ (Clockwise so $a$ to $b$ via $e$ )
