1. Tardigrade
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  4. In the case of thorium (A=232 and Z=90), we obtain an isotope of lead (A=208 and Z=82) after some radioactive disintegrations. The number of α-and β-particles emitted are, respectively,

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Q. In the case of thorium $(A=232$ and $Z=90)$, we obtain an isotope of lead $(A=208$ and $Z=82)$ after some radioactive disintegrations. The number of $\alpha$-and $\beta$-particles emitted are, respectively,

Nuclei

Solution:

Decrease in mass number $=232-208=24$
Number of $\alpha$-particles emitted $=\frac{24}{4}=6$
Due to emission of 6 particles, decrease in charge number is $12$.
But actual decrease in charge number is $8$.
Clearly, $4\, \beta$-particles are emitted.