Question

In the basic $CsCl$ crystal structure, $Cs ^{+}$ and $Cl ^{-}$ ions are arranged in a bcc configuration as shown in fig. The net electrostatic force exerted by the eight $Cs ^{+}$ ions on the $Cl ^{-}$ ion is

• A. $\frac{1}{4 \pi \epsilon_{0}} \frac{4 e^{2}}{3 a^{2}}$
• B. $\frac{1}{4 \pi \epsilon_{0}} \frac{16 e^{2}}{3 a^{2}}$
• C. $\frac{1}{4 \pi \epsilon_{0}} \frac{32 e^{2}}{3 a^{2}}$
• D. zero

Answer 1

Answer: (D)

Symmetry indicates the net electric field of $Cs^{+}$ ions at the centre is $0$