Thank you for reporting, we will resolve it shortly
Q.
In the arrangement shown in the figure $[sin\, 37^{\circ}=3/5]$
Laws of Motion
Solution:
Net driving force $= 60 - 40 = 20 \,N$ (down the plane)
As resisting force is greater than net driving force, the friction will be static of nature and friction force is $20\, N$ (up the plane)
