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Q. In the adjoining figure, four capacitors are shown with their respective capacities and the PD applied. The charge and the PD across the $ 4\mu F $ capacitor will bePhysics Question Image

Rajasthan PMTRajasthan PMT 2010

Solution:

Total capacitance $ \frac{1}{C}=\frac{1}{20}+\frac{1}{8}+\frac{1}{12} $ $ \Rightarrow $ $ C=\frac{120}{31}\mu F $ Total charge $ Q=CV=\frac{120}{31}\times 300=1161\mu C $ Charge through $ 4\mu F $ condenser $ =\frac{1161}{2}=500\mu C $ and potential difference across it $ =\frac{580}{4}=145\,\,V $