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  4. In the above question how many photons per second on an average are emitted by the source?

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Q. In the above question how many photons per second on an average are emitted by the source?

Dual Nature of Radiation and Matter

Solution:

If $N$ is the number of photons emitted by the
source per second, the power $P$ transmitted in the beam
equals $N$ times the energy per photon $E$, so that $P=N E$
$\Rightarrow N=\frac{P}{E}=\frac{2 \times 10^{-3} W }{3.98 \times 10^{-19} J }$
( $E$ was calculated in the last question)
$\Rightarrow N=5 \times 10^{15} s ^{-1}$