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Q. In terms of Rydberg constant R, the wavenumber of the first Balmer line is:

VMMC MedicalVMMC Medical 2006

Solution:

Wave number $ \bar{v}=\frac{1}{\lambda }=R\left( \frac{1}{{{n}_{1}}^{2}}-\frac{1}{{{n}_{2}}^{2}} \right) $ Here, $ {{n}_{1}}=2,\,{{n}_{2}}=3 $ $ \therefore $ $ \bar{v}\frac{5R}{36} $