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Q. In solid state, $N_{2}O_{5}$ exists as $\left[NO_{X}\right]^{+ }\left[NO_{Y}\right]^{-}.$
What is the value of $'X'?$

NTA AbhyasNTA Abhyas 2022

Solution:

In solid state, $N_{2}O_{5}$ exists as $\left[NO_{2}\right]^{+}\left[NO_{3}\right]^{-}.$
Hence, $'X'$ is $2.$