Question

In simple harmonic motion maximum velocity is at:

• A. extreme position
• B. half of extreme position
• C. equilibrium position
• D. between extreme and equilibrium position

Answer 1

Answer: (C)

In case of SHM, when motion is considered from the equilibrium position, velocity at an instant $t$ is given by $v=\omega \sqrt{A^{2}-y^{2}}$
At the mean or equilibrium position i.e., when $y=0$
$v=v_{\max }=\omega A$
At the extreme positions, i.e., when $y=\pm A$
$v=v_{\min }=0$ Hence, velocity is maximum at equilibrium position.