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Q.
In series $LCR$ circuit, the phase angle between supply voltage and current is
Alternating Current
Solution:
In series $L-c-R$ circuit, The impedance $z$ is $z=\sqrt{R^{2}+\left(x_{L}-x_{c}\right)^{2}}$
The current In lags the voltage $V_{C R}$ by an angle $\phi$,
If $x_{c}>x_{L}: V_{m c}>V_{m L}$, the current will lead the voltage
$\tan \phi=\frac{V_{m L}-V_{m c}}{V_{m R}}=\frac{X_{L} I_{m}-X_{c} I_{m}}{R I_{m}}$
$\tan \phi=\frac{x_{L}-x_{C}}{R}$
Hence the Phase angle b/w voltage and current in $L C R$ circuit is $\tan \phi=\frac{x_{L}-x_{C}}{R}$,