Question

In producing chlorine through electrolysis, $100\, kW$ power at $125\, V$ is being consumed. How much chlorine per minute is liberated?
$(ECE$ of chlorine is $0.367 \times 10^{-6}\, kg C^{-1})$

• A. $17.6 \times 10^{-3}\, kg$
• B. $16.6 \times 10^{-3}\, kg$
• C. $15.6 \times 10^{-3}\, kg$
• D. $14.6 \times 10^{-3}\, kg$

Answer 1

Answer: (A)

As $P=VI$
$\therefore I=\frac{P}{V}=\frac{100 \times10^{3}\,W}{125\,V}$
$=800\,A$
According to Faraday's first law of electrolysis
$m=ZIt$
Here, $Z=0.367 \times 10^{-6}\,kg\,C^{-1}$
$I=800\,A$
$t=1\,min=60\,s$
$\therefore m=\left(0.367 \times 10^{-6}\,kg\,C^{-1}\right)\left(800\,A\right)\left(60\,s\right)$
$=17.6\times10^{-3}\,kg$