Question

The variation of velocity of a particle executing SHM with time is shown in figure. the maximum displacement and acceleration of the particle are respectively:

• A. $\frac{10}{\pi} m$ and $5 \pi m / s ^{2}$
• B. $\frac{5}{\pi} m$ and $\frac{5 \pi}{2} m / s ^{2}$
• C. $\frac{10}{\pi} m$ and $\frac{5 \pi}{2} m / s ^{2}$
• D. $\frac{5}{\pi} m$ and $\frac{5 \pi}{4} m / s ^{2}$

Answer 1

Answer: (C)

Maximum displacement, $x_{\max }=A=\frac{10}{\pi} \cdot m$
and maximum acceleration, $a_{\max }=\omega^{2} A$
$=\left(\frac{\pi}{2}\right)^{2} \times \frac{10}{\pi}=\frac{5 \pi}{2} m / s ^{2}$