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  4. In photoelectric effect the slope of straight line graph between stopping potential (v0) and frequency of incident light (v) gives <img class=img-fluid question-image alt=Question src=https://cdn.tardigrade.in/q/nta/p-n9zkxmaegaso.png />

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Q. In photoelectric effect the slope of straight line graph between stopping potential $\left(v_{0}\right)$ and frequency of incident light $\left(v\right)$ gives

Question

NTA AbhyasNTA Abhyas 2020

Solution:

We know that
$E=\phi+kE$
$\Rightarrow h\upsilon=W+eV_{0}$
$\Rightarrow eV_{0}=h\upsilon-W$
$V_{0}=\left(\frac{h}{e}\right)\upsilon+\left(- \frac{W}{e}\right)$
Compare this with equation of line $y=mx+c$
$m=$ slope of graph $=\frac{h}{e}$