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  4. In oxygen difluoride ( OF 2) and dioxygen difluoride ( O 2 F 2), the oxygen is assigned an oxidation number of

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Q. In oxygen difluoride $\left( OF _{2}\right)$ and dioxygen difluoride $\left( O _{2} F _{2}\right)$, the oxygen is assigned an oxidation number of

Redox Reactions

Solution:

Electronegativity of fluorine is more than that of oxygen atom, so $F$ gains electron with negative charge.
In oxygen difluoride $\left( OF _{2}\right)$ and dioxygen difluoride $\left( O _{2} F _{2}\right)$, oxygen transfers electron to fluorine atom.
Thus, Oxidation number of oxygen in $OF _{2}=+2$
Oxidation number of oxygen in $O _{2} F _{2}=+1$.