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  4. In order to prepare one litre one normal solution of KMnO4, how many grams of KMnO4 are required, if the solution to be used in acidic medium for oxidation?

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Q. In order to prepare one litre one normal solution of $KMnO_4$, how many grams of $KMnO_4$ are required, if the solution to be used in acidic medium for oxidation?

The d-and f-Block Elements

Solution:

In acidic medium,
$\underset{\text{(From } KMnO_4)}{MnO_4^{-}} + 8H^+ + 5e^-\rightarrow Mn^{2+} + 4H_2O$
Thus, eq. wt. of $KMnO_4$ in acidic medium $ = \frac{\text{Mol. wt.}}{5}$
$ = \frac{158}{5} = 31.6$
$\therefore 1 \,N$ solution can be prepared by dissolving $31.6 \,g$ $KMnO_4$ in $1\, L$ solution.