Q. In order to balance a see-saw of total length 10.0 m, two kids weighing 20 kg and 40 kg are 'sitting at an end and at a distance x from the fulcrum at the centre, respectively. The value x (in cm) is
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Solution:
Consider the figure given below.
In balanced condition, net torque at the point O (fulcrum) is zero. $ \Rightarrow $ $ 20\times 5=40\times x $ $ \Rightarrow $ $ x=\frac{20\times 5}{40}=25 $ $ =250cm $
