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Physics
In open pipes, the positions of antinodes are obtained at
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Q. In open pipes, the positions of antinodes are obtained at ___
Oscillations
A
$0,\frac{\lambda}{2},2\lambda$
8%
B
$0,\frac{\lambda}{2},\lambda$
80%
C
$\frac{\lambda}{4},\frac{3\lambda}{4},\lambda$
6%
D
$\frac{5\lambda}{4},\frac{3\lambda}{4}$
6%
Solution:
In open pipes, position of antinodes is $\frac{ n \lambda}{2}$
Putting vales of $n$ as $o , 1,2$ we get position as $0, \lambda / 2, \lambda$