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Q. In octahedral complex, the value of the 'spin only' magnetic moment for one of the following configurations is $2.84 BM$. The correct one is

Coordination Compounds

Solution:

Spin only magnetic moment $=\sqrt{n(n+2)}$

Where $n=$ number of unpaired electrons.

$\sqrt{n(n+2)}=2.84 BM$ (given)

Hence, $n=2$

In octahedral complex a strong field ligand results in a low spin complex.

Thus, $d^{4}$ configuration has two unpaired electrons.

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