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Q. In nuclear fission, $0.1\%$ mass is converted into energy. The energy released by the fission of $1 \,kg$ mass is:

Rajasthan PMTRajasthan PMT 2004Nuclei

Solution:

$\Delta E=m c^{2}$
$\Delta E=\frac{0.1}{100} \times 9 \times 10^{16} \,J$
$=\frac{9 \times 10^{13}}{36 \times 10^{5}}\, kWh$
$=2.5 \times 10^{7} \,kWh$