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  4. In [Ni(NH3)4]SO4, the E.A.N. of Ni is

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Q. In $[Ni(NH_{3})_{4}]SO_{4},$ the E.A.N. of $Ni$ is

Coordination Compounds

Solution:

EAN = (atomic no) - (oxidation state) + (2 $\times$ number of Ligands) $= 2 8 - 2 + 2 \times 4 = 34$