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Q.
In methanol solution, bromine reacts with ethylene to yield $BrCH _{2} CH _{2} OCH _{3}$ in addition to $1,2$ - dibromoethane because
Hydrocarbons
Solution:
$CH_2= CH_2 + Br_2 \xrightarrow{CH_3OH^{+}} CH_2 - CH_2Br +Br^{-}$
Intermediate carbocation may react with $Br ^{-}$ or $CH _{3} OH$ to give distinct products.