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Q. In many situations, to find the electric field using the gauss law, we can use the simplified equation $\left|\overset{ \rightarrow }{E}\right|=\frac{q_{enclosed}}{\epsilon _{0} \left|\overset{ \rightarrow }{A}\right|}$ , where $\epsilon _{0}$ is the permittivity of free space, $A$ is the area of Gaussian surface and $q_{enclosed}$ is the net charge enclosed by the Gaussian surface. Among the following situations, this equation can be used

NTA AbhyasNTA Abhyas 2020Electrostatic Potential and Capacitance

Solution:

Magnitude of electric field is constant $\&$ the surface is equipotential