Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. In $Li^{++}$, electron in first Bohr orbit is excited to a level by a radiation of wavelength $\lambda$. when the ion gets deexcited to the ground state in all possible ways (including intermediate emissions), a total of six spectral lines are observed. What is the value of $\lambda$ ?
(Given : $h = 6.63 \times 10^{-34} \; Js ; c = 3 \times 10^8 \; ms^{-1})$ ;

JEE MainJEE Main 2019Atoms

Solution:

$\Delta E =\frac{hc}{\lambda} $
$ 13.6\times9-0.85 \times9 = \frac{hc}{\lambda} $
$\lambda = \frac{hc}{ 9 \times\left(13.6 -0.85\right)eV} $
$= \frac{1240eV .nm}{9\times12.75 eV} $
$ \lambda = 10.8\, nm $

Solution Image