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Q. In Lanthanide series, the element well known to exhibit $+4$ oxidation state is

AP EAMCETAP EAMCET 2018

Solution:

$Ce (58)=[ Xe ] 4 f^{1}\, 5 d^{1}\, 6 s^{2}$

$Ce ^{+4}=[ Xe ] 4 f^{0}\, 5 d^{0}\, 6 s^{0}$

Cerium exihibit $+4$ oxidation state.