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  4. In Kjeldahl's method, ammonia from 5 g of food neutralizes 30 cm3 of 0.1 N acid. The percentage of nitrogen in the food is

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Q. In Kjeldahl's method, ammonia from $5\, g$ of food neutralizes $30 \,cm^3$ of $0.1\, N$ acid. The percentage of nitrogen in the food is

KCETKCET 2010Organic Chemistry – Some Basic Principles and Techniques

Solution:

From Kjeldahl's method,

percentage of nitrogen

$=\frac{1.4 \times N \times V}{w}=\frac{1.4 \times 0.1 \times 30}{5}$

$=0.84 \%$