Question

In hydrogen atom, an electron is revolving in the orbit of radius $ 0.53\,\overset{\text{o}}{\mathop{\text{A}}}\, $ with $ 6.6\,\times {{10}^{15}} $ rotation/s. Magnetic field produced at the centre of the orbit is

• A. $ 0.125\,Wb/{{m}^{2}} $
• B. $ 1.25\,Wb/{{m}^{2}} $
• C. $ 12.5\,Wb/{{m}^{2}} $
• D. $ 125\,\,Wb/{{m}^{2}} $

Answer 1

Answer: (C)

The magnetic field at the centre of the orbit $ B=\frac{{{\mu }_{0}}}{4\pi }\cdot \frac{2\pi (qv)}{r} $ $ ={{10}^{-7}}\times \frac{2\times 3.14\times (1.6\times {{10}^{-19}}\times 6.6\times {{10}^{15}})}{0.53\times {{10}^{-10}}} $ $ =12.5\,\,Wb/{{m}^{3}} $