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Q.
In how many ways can 6 persons be seated round a circular table when two particular persons sit
together ?
Permutations and Combinations
Solution:
First of all let two particular persons be seated together. They can sit together in $2! = 2$ ways.
Then the remaining four persons may sit on remaining four places in $4 ! = 24$ ways, so the total number
of ways
$=2 \times 24=48$