Question

In how many of the following molecules, all atoms are in same plane?

$ClF_{3}$	$H_{2}O$	$PCl_{3}$	$BF_{3}$
$SF_{4}$	$H_{2}S$	$OCl_{2}$	$SO_{3}$
$XeF_{6}$	$NH_{3}$	$C_{6}H_{6}$	$XeF_{2}$
$XeF_{4}$	$PCl_{5}$	$I_{2}Cl_{6}$	$PH_{3}$

• A. 12
• B. 0
• C. 10
• D. 11

Answer 1

Answer: (C)

Planar molecules

$ClF_{3},XeF_{4},H_{2}O, \, H_{2}S, \, OCl_{2}, \, C_{6}H_{6}, \, I_{2}Cl_{6}, \, BF_{3}, \, SO_{3},XeF_{2}$

$ClF_{3} \rightarrow $ Central atom $Cl$ has $2.lp+3Bp=sp^{3}d$ hybridised it is T-shape (planar)

$H_{2}O \rightarrow $ Central atom $O-$ has $2lp+2Bp=sp^{3}$ hybridised (angular)( planar)

$PCl_{3} \rightarrow $ Central atom $P-$ has $1lp+3p \rightarrow sp^{3}$ hybridised pyramidal (non planar)

$BF_{3} \rightarrow sp^{2}$ hybridised $ \rightarrow $ triagonal planar (planar)

$SF_{4} \rightarrow CentralatomS$ has $\left(1 l p + 4 B p\right),sp^{3}d$ hybridised see-saw structure (non planar)

$H_{2}S \rightarrow CentralatomS$ has $2lp+2bp$ angle between $H-\overbrace{S}H$ is $90^\circ $ (planar)

$OCl_{2} \rightarrow CentralatomO-$ has $2lp+2bp$ ; angular shape (planar)

$SO_{3} \rightarrow sp^{2}$ hybridised, triangonal (planar)

$XeF_{6} \rightarrow 6Bp-sp^{3}d^{2}$ hybridised/ square bipyramidal (non-planar)

$NH_{3} \rightarrow 1lp+3Bp \rightarrow sp^{3}$ hybridised ( pyramidal (non-planar)

$C_{6}H_{6} \rightarrow $ in benzene all $C-$ atoms are $sp^{2}$ and planar molecule.(planar)

$XeF_{2} \rightarrow 3lp+2Bp;-sp^{3}d$ hybridised ,linear shape(planar).

$XeF_{4} \rightarrow 1lp+4Bp \rightarrow sp^{3}d$ hybridised structure see-saw (non-planar)

$PCl_{5} \rightarrow 5Bp \rightarrow sp^{3}d$ hybridised TBP (non-planar)

$I_{2}Cl_{6} \rightarrow $

dimer (planar)

$PH_{3} \rightarrow 1lp+3Bp \rightarrow sp^{3}$ hybridised/ pyramidal (non-planar)