Question

In Hoffmann bromamide degradation, one of the important steps is the migration of:

• A. An alkyl group without its electron pair to electron deficient $N$ atom.
• B. An alkyl group with its electron pair to electron deficient $O$ atom.
• C. An alkyl group with its electron pair to electron rich $N$ atom.
• D. An alkyl group with its electron pair to electron deficient $N$ atom.

Answer 1

Answer: (D)

For this one should remember that Hoffmann's degradation involves migration to electron deficient nitrogen atom, hence the alkyl group will migrate with its bonding pair of electrons.