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  4. In heat engine, sink is fitted at temperature 27° C and heat of 100 kcal is taken from source at temperature 677° C. Work done is

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Q. In heat engine, sink is fitted at temperature $27^{\circ} C$ and heat of 100 kcal is taken from source at temperature $677^{\circ} C$. Work done is

Thermodynamics

Solution:

$\eta=\frac{W}{Q_{1}}=1-\frac{T_{2}}{T_{1}}=1-\frac{300}{950}$
$\frac{W}{Q}=\frac{13}{19}$ cal
$W =10^{2} \times 10^{3} \times \frac{13}{19} \times 4.2 J$
$W =0.28 \times 10^{6}$ Joule