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  3. Chemistry
  4. In hcp (ABAB...) and ccp (ABCABC...) structures made up of spheres of equal size, the volume occupied per sphere (including the empty spaces) is ( a= radius of sphere) :

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Q. In hcp $(ABAB...)$ and ccp $(ABCABC...) $ structures made up of spheres of equal size, the volume occupied per sphere (including the empty spaces) is ( $a=$ radius of sphere) :

The Solid State

Solution:

so, volume of unitcell in ${ccp}=\left(\frac{4 a}{\sqrt{2}}\right)^{3}$
so volume per spheric/atom $=\frac{1}{4} \times \frac{64 a^{3}}{2 \sqrt{2}}$
$=0.566 \,a^{3}$.