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  4. In glycolysis, there is one step where NADH + H +is formed from NAD +, this is when 3-phosphoglyceraldehyde (PGAL) is converted to 1, 3-bisphosphyglycerate (BPGA). This reaction shows

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Q. In glycolysis, there is one step where $NADH + H ^{+}$is formed from $NAD ^{+}$, this is when 3-phosphoglyceraldehyde (PGAL) is converted to 1, 3-bisphosphyglycerate (BPGA). This reaction shows

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Solution:

In glycolysis, we find that there is one step where $NADH + H ^{+}$is formed from $NAD ^{+}$; this is when 3phosphoglyceraldehyde (PGAL) is converted to 1, 3bisphosphoglycerate (BPGA). Two redox equivalents are removed (in the form of two hydrogen atoms) from PGAL and transferred to a molecule of NAD.