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Physics
In given LCR circuit, the voltage across the terminals of a resistance R and current through ammeter will bef
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Q. In given LCR circuit, the voltage across the terminals of a resistance R and current through ammeter will be$f$
A
$200\, V ; 5\, A$
44%
B
$400 \,V ; 5\, A$
33%
C
$4007, V ; 5 \sqrt{2} \,A$
0%
D
$200\, V ; 5 \sqrt{2}\, A$
22%
Solution:
$V=\sqrt{V_{R}^{2}+\left(V_{L}-V_{C}\right)^{2}}$
$\Rightarrow V=V_{R}=200 \,V$
$\Rightarrow I=\frac{V}{Z}=\frac{V}{\sqrt{R^{2}+\left(X_{L}-X_{C}\right)^{2}}}$
$=\frac{200}{40}=5\, A$