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Q. In Friedel-Craft's reaction, anhydride. $ AlCl_{3} $ acts to:

BHUBHU 2001

Solution:

During Friedel-Craft reaction alkyl or acyl group replaces hydrogen of benzene ring. Anhydrous $AlCl _{3}$ produces electrophile.
$R Cl +\underset{\text{ Anhy} . AlCl _{3}}{ AlCl _{3}} \rightleftharpoons R ^{+}+\underset{\text { Electrophile }}{ AlCl _{4}^{-}}$
$R^{+}+ C _{6} H _{6} \longrightarrow { C }_{6} H _{5} Cl + H ^{+}$
$AlCl _{4}^{-}+ H ^{+} \longrightarrow AlCl _{3}+ HCl$