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Q. In Freundlich adsorption isotherm, slope of AB line is :Chemistry Question Image

JEE MainJEE Main 2021Surface Chemistry

Solution:

$\frac{x}{m}=K(P)^{1 / n}$

$\log \left(\frac{ x }{ m }\right)=\log K +\frac{1}{ n } \log P$

$y = c + mx$

$m =1 / n$ so slope will be equal to $1 / n$

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Hence $0 \le \frac{1}{n} \le 1$