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Q. In figure, two equal positive point charges $q_{1}=q_{2}=2.0$ $\mu C$ interact with a third point charge $Q=4.0\, \mu C$. The magnitude, as well as direction, of the net force on $Q$ is
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Electric Charges and Fields

Solution:

$F_{\text {net }}=2\left|F_{31}\right| \cos \alpha$
$=2 \times \frac{1}{4 \pi \varepsilon_{0}} \times \frac{2 \times 4 \times 10^{-12}}{(0.5)^{2}} \times \frac{4}{5}=0.46\, N $

Solution Image