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Q.
In figure, charge on the capacitor is plotted against potential difference across the capacitor. The capacitance and energy stored in the capacitor are respectively.
KCETKCET 2021Electrostatic Potential and Capacitance
Solution:
$q = CV $
$ C =\frac{ q }{ V }=\frac{120 \times 10^{-6}}{10}=12 \times 10^{-6} F $
$ C =12 \,\mu F $
$ U =\frac{1}{2} CV ^{2}$
$=\frac{1}{2} \times 12 \times 10^{-6} \times 10 \times 10 $
$ U =600 \times 10^{-6} J $
$ U =600 \,\mu J $