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Q. In figure below, the point charge $Q_{1}$ causes an electric potential of $60 \,V$ and an electric field strength of $30 \,V m ^{-1}$ at $P$ and the point charge $Q_{2}$ separately causes a potential of $120\, V$ and a field strength of $40\, V m ^{-1}$ at $P$.
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Which one of the following gives possible value of potential and filed strength at $P$ due to the joint action of $Q_{1}$ and $Q_{2}$ ?
Potential(V) Field(V $m ^{-1}$ )
a 180 70
b 180 50
c 135 50
d 60 10

Electrostatic Potential and Capacitance

Solution:

The electric potential at $P$ due to charges $Q_{1}$ and $Q_{2}$ is the algebraic sum of the potentials due to individual charges at point $P .$ Hence, the electric potential at is now $(120+60)$ or $180\, V$.
On the other hand, the electric field strength at $P$ is the resultant of fields due to charges $Q_{1}$ and $Q_{2}$. The value of the resultant field strength is $50\, V\, m ^{-1}$ as shown.
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