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  4. In figure, a straight line is given for Freundrich Adsorption (y=3 x+2.505). The value of (1/ n ) and log K are respectively.

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Q. In figure, a straight line is given for Freundrich Adsorption $(y=3 x+2.505)$. The value of $\frac{1}{ n }$ and $\log K$ are respectively.Chemistry Question Image

JEE MainJEE Main 2023Surface Chemistry

Solution:

$\frac{ x }{ m }= Kp ^{1 / n } $
$ \log \frac{ x }{ m }=\log k +\frac{1}{ n } \log P $
$ \left. Y =3 x +2.505, \frac{1}{ n }=3, \log K =2.505\right)$