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  4. In fcc lattice, edge length is 400 pm. Find the diameter of the greatest sphere which can be fitted into the interstitial void without distortion of lattice:

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Q. In fcc lattice, edge length is $400\, pm$. Find the diameter of the greatest sphere which can be fitted into the interstitial void without distortion of lattice:

The Solid State

Solution:

For fcc, $r=\frac{a}{2 \sqrt{2}}=\frac{400}{2 \sqrt{2}}=141.4\, pm$

Radius of Octahedral void $( r )=0.414\, R$

$=0.414 \times 141.4$

$=58.54\, pm$

Diameter $=2 \times 58.54=117.08\, pm$