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  4. In Dumas method, 0.3 g of an organic compound gave 45 mL of nitrogen at STP. The percentage of nitrogen is

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Q. In Dumas method, $0.3\, g$ of an organic compound gave $45\, mL$ of nitrogen at STP. The percentage of nitrogen is

AP EAMCETAP EAMCET 2016

Solution:

In Dumas method,

From the volume of $N _{2}$ at $STP$, the percentage of nitrogen is calculated as

$\% $ of nitrogen $=\frac{28 \,V \times 100}{22400 \times W }$

Here, $V=$ volume of $N _{2}$ evolved at STP

$W=$ weight of organic compound taken

$W=0.3 \,g $

$V=45\, mL $

$\% $ Nitrogen $=\frac{V}{8 W} $

$=\frac{45}{8 \times 0.3} $

$=18.75$