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Q. In drawing of a card from a well shuffled ordinary deck of playing cards the events card drawn is spade' and 'card drawn is an ace' are

Probability - Part 2

Solution:

Let $A$ : card is spade
$B$ : card is an ace.
$P(A)=\frac{13}{52} $
$ P(B)=\frac{4}{52}$
$P(A \cap B)=\frac{1}{52} $