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Q. In diamond, each carbon atom is bonded to four other carbon atoms tetrahedrally. The number of carbon atoms per unit cell is

The Solid State

Solution:

Structure of diamond can be visualised as an $f.c.c.$ arrangement of carbon atoms in which carbon atoms are also present in alternate tetrahedral sites. In such a way each carbon atom has a $C.N$. of $4$.
No. of atoms per unit cell.
$ = 8\times \frac{1}{8} + 6 \times \frac{1}{2} +4 \times 1$
$ = 1 + 3 + 4 = 8$
(Eight corners, six face centres and half of the $8$ tetrahedral sites)