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Q.
In $ Cu\,\,(At.\,\,No.29) $
Rajasthan PMTRajasthan PMT 2010
Solution:
$ Cu $ (Atomic no. $ =29 $ ) $ =1{{s}^{2}},\,\,2{{s}^{2}}2{{p}^{6}},\,\,3{{s}^{2}}3{{p}^{6}}3{{d}^{10}},\,\,4{{s}^{1}} $ $ \because $ In an orbital the two electrons must have the opposite spin. $ \therefore $ In $ Cu\, $ , $ 14 $ electrons have spin in one direction and $ 15 $ electrons in other direction.