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  4. In Cu-ammonia complex, the state of hybridization of Cu+2 is

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Q. In $Cu$-ammonia complex, the state of hybridization of $Cu^{+2}$ is

WBJEEWBJEE 2009Coordination Compounds

Solution:

$Cu$-ammonia complex is $\left[ Cu \left( NH _{3}\right)_{4}\right]^{2+}$
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$NH_3$, being strong field ligand, shifts the unpaired electron to higher level.