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  4. In corundum, oxide ions have h c p arrangement. What percentage of octahedral voids are occupied by Al?

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Q. In corundum, oxide ions have $h c p$ arrangement. What percentage of octahedral voids are occupied by $Al$?

The Solid State

Solution:

Corundum is $Al _{2} O _{3}$.

For $3 O ^{2-}$ ions, octahedral sites are 3 . Out of three sites, only 2 are occupied by $Al ^{3+}$ ions.

$\therefore $ Sites occupied by $Al ^{3+}$ ions $=\frac{2}{3} \times 100=66 \%$