1. Tardigrade
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  3. Chemistry
  4. In chemical equilibrium, the value of Δ n is negative, then the relationship between Kp and Kc will be

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Q. In chemical equilibrium, the value of $\Delta n$ is negative, then the relationship between $K_p$ and $K_c$ will be

JIPMERJIPMER 2012Equilibrium

Solution:

$K_p = K_c (RT)^{(\Delta n)}$
When $\Delta n = -ve or \Delta n < 0$,
$K_p < K_c$