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Q. In Carius method of estimation of halogens, $355\, mg$ of an organic compound gave $287\, mg$ of $AgCl$. The percentage of chlorine in the compound is______ .
(At. Mass: $Ag =108 ; Cl =35.5\, u$ )

Organic Chemistry – Some Basic Principles and Techniques

Solution:

$\%$ of chlorine
$=\frac{35.5 \times \text { Mass of } AgCl }{143.5 \times \text { Mass of organic compound }} \times 100$
$=\frac{35.5 \times 0.287 \times 100}{143.5 \times 0.355}=20 \%$