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Q. In $CaF_2$ type (fluorite structure) $Ca^{2+}$ ions form $(A)$ structure and $F^-$ ions are present in all $(B)$ voids. The coordination number of $Ca^{2+}$ is $(C)$ and $F^-$ is $(D)$.
$(A)$, $(B)$, $(C)$ and $(D)$ respectively are
$A$ $B$ $C$ $D$
(a)$\,\,$ $ccp\,\,$ octahedral$\,$ $8\,\,$ $4\,\,$
(b)$\,\,$ $bcc\,\,$ tetrahedral$\,\,$ $4\,\,$ $8\,\,$
(c)$\,\,$ $ccp\,\,$ tetrahedral$\,\,$ $8\,\,$ $4\,\,$
(d)$\,\,$ $ccp$ octahedral$\,\,$ $4$ $8\,\,$

The Solid State

Solution:

$Ca^{2+}$ ions form $ccp$ structure while $F^-$ ions are in all tetrahedral holes and coordination numbers are $8$ and $4$.